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Find the point P where the line x = 1 + t, y = 2t, z = -3t intersects the plane x + y - z = -1. Help please.
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I have -2t=-7+3s & 1+2t=5s & 3t=1+5s. Where do I go from here?
If I isolate each variable, I get that t = 7/2 and s = 19/10, I am lost after that. I don't know what to do. Help please.
hey
did you try replace putting x+y-z=-1 in terms of t
\[x+y-z=-1 \\ (1+t)+(2t)-(-3t)=-1\] Solve this for t
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then you can find (x,y,z) the point of intersection
(x,y,z)=(1+t,2t,-3t)
Are you here?
yes I am
so you are saying that the result would be (0, -2, 3). Is that right?
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what did you get for t?
-1/3 = t
ok isn't 1+(-1/3)=2/3
that would be the x-coordinate
and y=2t=2(-1/3)=-2/3 and z=-3t
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so z=?
1
yep
okay I got it now. Thank you very much.
np
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