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Mathematics 11 Online
OpenStudy (anonymous):

• Mr. Romano: He says that 2 is a zero of g(x) because synthetic division with 2 results in a remainder of 0.

OpenStudy (anonymous):

Mr. Romano is right because if 2 is a factor of g(x), it will allow 2 to have 0 as the remainder. Remainder theorem.

OpenStudy (anonymous):

is this correct?

OpenStudy (anonymous):

well actually \(x-2\) would be a factor of \(g(x)\) not \(2\)

OpenStudy (anonymous):

Correct the reasoning of any inaccurate reasoning by the partygoers in full and complete sentences. Make sure you reference any theorems that support your justifications. forgot to post this

OpenStudy (anonymous):

Ok does everything else with it look good? Mind checking these?

OpenStudy (anonymous):

Ms. Guerra: She says that 2 is a zero of g(x) because g(2) = 0. -Ms. Guerra is right because when 2 is a zero of g(x), g (2) = is 0. You can come up with this from the remainder theorem and the definition of a root. Professor McCoy: She says that 2 is a zero of g(x) because long division with (x + 2) results in a remainder of 0. -Professor McCoy is wrong because for 2 to be a 0 of g(x), it must be (x – 2) but she is using (x + 2).

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@SolomonZelman @iambatman

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