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Mathematics 21 Online
OpenStudy (anonymous):

Let f(x) =ln(x-5)+2 , i need the y intercept from that and the range of the inverse function

OpenStudy (anonymous):

\[x=\ln(y-5)+2\] solve for \(y\) in three steps

OpenStudy (anonymous):

subtract 2 rewrite in exponential form add 5

OpenStudy (xapproachesinfinity):

the range of the inverse is the domain of f(x)?

OpenStudy (anonymous):

always

OpenStudy (xapproachesinfinity):

I know @satellite73 i'm asking him is he sure about what he wrote

OpenStudy (xapproachesinfinity):

indirectly though lol

OpenStudy (anonymous):

wait what?

OpenStudy (xapproachesinfinity):

you are asked to find the range of the inverse the same as asking you to find the domain of f(x)

OpenStudy (anonymous):

oh sorry i did not see that was you @xapproachesinfinity

OpenStudy (anonymous):

@alexxiscouture did you find \(f^{-1}(x)\) yet?

OpenStudy (anonymous):

no, i don't know how to do this at all, break it down some more

OpenStudy (mathmale):

"Let f(x) =ln(x-5)+2 , i need the y intercept from that and the range of the inverse function." Whoa. Ask yourself: What is the domain of the natural log function? Then, ask yourself: What is the domain of ln (x-5)? If the graph of a function has a y-intercept, x must necessarily be zero. What are the implications of that in this particular problem?

OpenStudy (xapproachesinfinity):

@satellite73 no worries

OpenStudy (anonymous):

nvm i got it

OpenStudy (xapproachesinfinity):

is the question written correctly?

OpenStudy (anonymous):

yes

OpenStudy (xapproachesinfinity):

ok

OpenStudy (xapproachesinfinity):

so what do you think about y intercep

OpenStudy (mathmale):

Playing devil's advocate: What would happen if you were to set x = to zero, which is the usual way of determining the y-value of the y-intercept?

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