Form a polynomial f(x) with real co-efficients having the given degree and zeros. a. Degree 4; zeros: -5-5i; multiplicity 2 b. Degree 5; zeros: -5; -i-7i+i c. Degree 4; zeros: 5; multiplicity 2;2i
if -5-5i is a root, then so is -5+5i because complex roots come in conjugate pairs
each roots is of multiplicity 2
so you have something like (x - (-5-5i) )^2 * (x - (-5+5i) )^2
this is for part a)
would i distribute the negative?
yes you would
i distributed it and it said it was wrong and it changed the first part of the problem to Degree 4; zeros 2+4i; 5; multiplicity 2... would i just follow the same steps
2+4i is a zero so 2-4i is a zero 5 is a root of multiplicity two, so (x-5)^2 is a factor
2+4i is a zero ---> (x - (2+4i)) is a factor 2-4i is a zero ---> (x - (2-4i)) is a factor
Join our real-time social learning platform and learn together with your friends!