Form a polynomial f(x) with real co-efficients having the given degree and zeros.
a. Degree 4; zeros: -5-5i; multiplicity 2
b. Degree 5; zeros: -5; -i-7i+i
c. Degree 4; zeros: 5; multiplicity 2;2i
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jimthompson5910 (jim_thompson5910):
if -5-5i is a root, then so is -5+5i because complex roots come in conjugate pairs
jimthompson5910 (jim_thompson5910):
each roots is of multiplicity 2
jimthompson5910 (jim_thompson5910):
so you have something like
(x - (-5-5i) )^2 * (x - (-5+5i) )^2
jimthompson5910 (jim_thompson5910):
this is for part a)
OpenStudy (anonymous):
would i distribute the negative?
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jimthompson5910 (jim_thompson5910):
yes you would
OpenStudy (anonymous):
i distributed it and it said it was wrong and it changed the first part of the problem to Degree 4; zeros 2+4i; 5; multiplicity 2... would i just follow the same steps
jimthompson5910 (jim_thompson5910):
2+4i is a zero so 2-4i is a zero
5 is a root of multiplicity two, so (x-5)^2 is a factor
jimthompson5910 (jim_thompson5910):
2+4i is a zero ---> (x - (2+4i)) is a factor
2-4i is a zero ---> (x - (2-4i)) is a factor