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Mathematics
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Chapter Death
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\[\frac{ 7-lnx }{ x(3+lnx) }dx\]
Integrate
What would ganeshie do...Sub u = lnx, du = 1/x dx
I guess you'll have to do long division as well
and maybe another substitution xD
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What. No.
u sub -> long division -> another substitution
When I substitute, I get (7-u)/(3+u) *du
Yeah so do long division now
How do I deal with the remainder?
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What did you get?
7/3 R 4/3u
Or just let \(u=3+\ln x\). The integral then becomes \(\displaystyle \int\frac{10-u}{u}\,du = \int\frac{10}{u}-1\,du\)
INTERESTING
Integrals are interesting indeed. XD
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\[\int\limits \frac{ 10 }{ u+3 }-1 du\]
let t = u+3, dt = du
\[10 \int\limits \frac{ 1 }{ t }dt- \int\limits 1 du \implies 10\ln(lnx+3)-lnx+C\]
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