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Mathematics 21 Online
OpenStudy (anonymous):

Chapter Death

OpenStudy (anonymous):

\[\frac{ 7-lnx }{ x(3+lnx) }dx\]

OpenStudy (anonymous):

Integrate

OpenStudy (anonymous):

What would ganeshie do...Sub u = lnx, du = 1/x dx

OpenStudy (anonymous):

I guess you'll have to do long division as well

OpenStudy (anonymous):

and maybe another substitution xD

OpenStudy (anonymous):

What. No.

OpenStudy (anonymous):

u sub -> long division -> another substitution

OpenStudy (anonymous):

When I substitute, I get (7-u)/(3+u) *du

OpenStudy (anonymous):

Yeah so do long division now

OpenStudy (anonymous):

How do I deal with the remainder?

OpenStudy (anonymous):

What did you get?

OpenStudy (anonymous):

7/3 R 4/3u

OpenStudy (anonymous):

Or just let \(u=3+\ln x\). The integral then becomes \(\displaystyle \int\frac{10-u}{u}\,du = \int\frac{10}{u}-1\,du\)

OpenStudy (anonymous):

INTERESTING

OpenStudy (anonymous):

Integrals are interesting indeed. XD

OpenStudy (anonymous):

\[\int\limits \frac{ 10 }{ u+3 }-1 du\]

OpenStudy (anonymous):

let t = u+3, dt = du

OpenStudy (anonymous):

\[10 \int\limits \frac{ 1 }{ t }dt- \int\limits 1 du \implies 10\ln(lnx+3)-lnx+C\]

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