Question

Solve each of these systems using the substitution method.
2x + 3y = -4
x − 2y = 5
Answer

x = 1, y = -2

x = -1, y = 2

x = 1, y = 2

x = -2, y = -1

Question 2

2x − y = -2
3y = 6 − 5x
Answer

x = 0, y = 2

x = 2, y = 0

x = 2, y = 2

x = 0, y = -2

Question 3

2x − y = 4
6x − 3y = 7
Answer

y = 2x - 4

No solution

x = 2, y = -4

x = 2, y = 5/3

Question 4

2x − y = 3
4x = 6 + 2y
Answer

Infinitely many solutions

x = 2, y = 1

y = 2x - 3

x = 4, y = 5

sos please help!

Answer 1

Using substitution method
2x + 3y = -4 ----equation 1
x - 2y = 5 ----equation 2
from equation 2
x - 2y = 5
x = 2y + 5 ----equation 2'
substitute equation 2' to equation 1
2x + 3y = -4
2(2y+5) + 3y = -4
4y + 10 + 3y = -4
4y + 3y = -4 - 10
7y = -14
y = -2
substitute y=-2 to equation 2'
x = 2y + 5
x = 2(-2) + 5
x = -4 + 5
x = 1

Answer 2

using the same method, can you do the next system of equations?

Answer 3

im doing a math quiz rn bcs im homeschooled can u just help solve to other ones and thats it please it would mean alot

Answer 4

but did you understand it though? (-_-)!

Answer 5

i understand little bits of it.

Answer 6

okay i'm gonna solve it but ask me those things that confuses you or those that you don't understand. okay?

Answer 7

yeah sure

Answer 8

2x - y = -2 ----equation 1
3y = 6 - 5x ----equation 2
from equation 1
2x - y = -2
2x + 2 = y
y = 2x + 2 -----equation 1'
substitute equation 1' to equation 2
3y = 6 - 5x
3(2x + 2) = 6 - 5x
6x + 6 = 6 - 5x
6x + 5x = 6 - 6
11x = 0
x = 0
substitute x=0 to equation 1'
y = 2x + 2
y = 2(0) + 2
y = 2

Answer 9

2x - y = 4 ----equation 1
6x - 3y = 7 ----equation 2
from equation 1
2x - y = 4
2x - 4 = y
y = 2x - 4 ----equation 1'
substitute equation 1' to equation 2
6x - 3y = 7
6x - 3(2x - 4) = 7
6x - 6x + 12 = 7
6x - 6x = 7 -12
0 is not equal to -5
for this case, there's no solution.
there could be no values of x and y that would be true to both equations

Answer 10

2x - y = 3 ---equation 1
4x = 6 + 2y ----equation 2
from equation 1
2x - y = 3
2x - 3 = y
y = 2x - 3 ---equation 1'
substitute equation 1' to equation 2
4x = 6 + 2y
4x = 6 + 2(2x - 3)
4x = 6 + 4x - 6
4x - 4x = 6 - 6
0=0
in this case where the variable becomes zero as the constant is zero, then we can say that the two equations are equal that whatever values of x and y you substitute, will be true to the two equations. the system does have an infinite solution

Answer 11

but thats not in the choices o.o