If lim inferior a_{n} = a, a in R and lim n->infinity b_{n} = b > 0, show lim inferior (a_{n}b_{n}) = ab
If \(\lim \inf\ {{n\rightarrow\infty}}\) \((a_{n}) = a, a \in\mathbb{R}\) and \(\lim_{n \rightarrow \infty } b_{n} = b >0\), show \(\lim \inf\ {{n\rightarrow\infty}}\) \((a_{n}b_{n}) = ab\) Trying to get used to typing all of this up my hand (and couldnt figure out how to type lim inferior), but wanted to make sure the question made sense.
I think this will work if you use the definition of a limit: \[\forall \epsilon>0 \exists N \in \mathbb{N} a_{n}>b-\epsilon\]
Typo : \(a_{n}> a - epsilon\)
Im not sure how to relate that to limit inferior and superior, though. I've kind of set up the inequality definitions for inferior, superior, and regular limits, but I cant relate the two.
Show that \(\liminf_{n \to \infty} b_n = b\) the rest should be easy.
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