12/7 = -6y I have to find the value of y Can someone explain?
\[-6y = \frac{12}{7}\]
Can you explain?
Wait, I have not done anything yet.
See, can you see we want to get \(y\), but \(y\) is not alone, \(-6\) os our enemy, it is not leaving \(y\) for us, getting?
mhm.. but Im still not exactly sure how to solve..
For that I am here, just tell me what I am saying to you, are you getting?
so far, yes
So, we need to get rid of \(-6\).. See, when we divide by -6, on both the sides, then what will you get?
I show you: \[\frac{-6y}{-6} = \frac{\frac{12}{7}}{-6}\]
I have divided by \(-6\) both the sides.
Okay up to here?
Mhm
So, on left hand side, \(-6\) and \(-6\) will get cancelled, giving you your \(y\).
\[\frac{\cancel{-6}y}{\cancel{-6}} = \frac{\frac{12}{7}}{-6} \implies y= \frac{\frac{12}{7}}{-6}\]
The right hand side can be simplified more.
\[y = \frac{\frac{12}{7}}{-6} \implies y = \frac{12}{7 \times (-6)} \implies y = \frac{\cancel{12}^2}{7 \times (- \cancel{6}^1)} \implies \color{green}{y = \frac{-2}{7}}\]
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