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Mathematics 25 Online
OpenStudy (anonymous):

Just a couple verification. PLEASE :)

OpenStudy (anonymous):

This is about concave up and down. \(\large\color{black}{ a) }\) when \(\large\color{black}{ f''(x)>0 }\) the \(\large\color{black}{ f(x) }\) is concave up. \(\large\color{black}{ b) }\) when \(\large\color{black}{ f''(x)<0 }\) the \(\large\color{black}{ f(x) }\) is concave down. \(\large\color{black}{ c) }\) when \(\large\color{black}{ f''(x)=0 }\) the \(\large\color{black}{ f(x) }\) has an inflection point e.i. a local max or min, and that is a concavity change in a function.

OpenStudy (perl):

c) is not necessarily true

OpenStudy (perl):

f(x) = x^4 , f ' (x ) = 4x^3, f ' ' (x) = 12x^2 = 0 , x = 0. but 0 is not an inflection point

OpenStudy (anonymous):

When is it not true? When the function is a parabola?

OpenStudy (perl):

definition of inflection point , the concavity changes at the point.

OpenStudy (anonymous):

yes

OpenStudy (perl):

well you have to do more work to determine its a true inflection point

OpenStudy (perl):

there are other cases

OpenStudy (perl):

we make a sign chart and test the second derivative to the right and left of the potential inflection point

OpenStudy (perl):

test values

OpenStudy (anonymous):

but parabola is one of the cases, because it has no inflection points, since the slope is always increasing or always decreasing.

OpenStudy (perl):

, no y = x^2 the slope is not always increasing

OpenStudy (perl):

or y = x^4

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

in y=x^2, when the x --> negative infinity the slope of the function is a very big negative slope, and then as x becomes closer to zero, the slope becomes zero, and as x --> positive infinity the slope of the function is positive.

OpenStudy (anonymous):

(sorry )

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