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OpenStudy (anonymous):

What is the equation of the graph below?

OpenStudy (anonymous):

OpenStudy (anonymous):

y = -2(x - 3)2 + 1 y = -2(x + 3)2 + 1 y = 2(x - 3)2 + 1 y = 2(x + 3)2 + 1

OpenStudy (anonymous):

@cwrw238 PLZ HELP ME

OpenStudy (anonymous):

@johnweldon1993

OpenStudy (johnweldon1993):

Alright...first off...we know this is parabola...so we know its gonna be some type of variation from \[\large y = x^2\] right?

OpenStudy (anonymous):

right

OpenStudy (johnweldon1993):

So if we look at that |dw:1415219933534:dw|

OpenStudy (johnweldon1993):

Well we can see that yours is upside down....so that means we would have a |dw:1415219978110:dw| okay? So there, all we need to do is move it up 1...and then over to the right 3 any idea how to do that?

OpenStudy (anonymous):

dont think i do :/

OpenStudy (johnweldon1993):

Put a smile on that pretty face :) that's why I'm here to help :)

OpenStudy (anonymous):

:) thank you so much!

OpenStudy (anonymous):

i know the answer will be either B or D

OpenStudy (anonymous):

right?

OpenStudy (johnweldon1993):

So, we know that when we add or subtract a number from a function....we actually shift the graph up or down For example: \[\large y = x\] and \[\large y = x+1\]looks like |dw:1415220157648:dw|

OpenStudy (johnweldon1993):

So here its the same thing.... We have an upside down parabola that starts at y = 0....and we want to shift it up to 1 so \[\large y = -x^2 + 1\]

OpenStudy (anonymous):

is it C?

OpenStudy (johnweldon1993):

Now we just need to figure out how to move it to the right by 3... Well , for that we just add or subtract a number from the 'x' if we add...we move to the left....if we subtract...to the right...so here we need to subtract 3 from the x \[\large y = -(x - 3)^2 + 1\]

OpenStudy (johnweldon1993):

No it wouldnt be C because we need that '-' out in front to make it be upside down :)

OpenStudy (anonymous):

oh A lol

OpenStudy (anonymous):

I also have a question that's kind of similar to this one and I just want you to check my answer. I already have the answer. Do you mind?

OpenStudy (johnweldon1993):

Of course not :)

OpenStudy (anonymous):

Thank you very much! so sweet!!

OpenStudy (johnweldon1993):

Just for you :)

OpenStudy (anonymous):

Use the graph below to answer the following question:

OpenStudy (anonymous):

OpenStudy (anonymous):

What is the average rate of change from x = -1 to x = 1? -4 -2 2 <------ MY ANSWER 4

OpenStudy (johnweldon1993):

Hmm....not quite what I get... \[\large \frac{f(b) - f(a)}{b - a}\] right?

OpenStudy (anonymous):

yea

OpenStudy (johnweldon1993):

Or maybe I'm doing it wrong lol we're at -3 at f(1) and 1 at f(-1) so \[\large \frac{-3 - 1}{1 - (-1)} = \frac{-4}{2} = -2\]

OpenStudy (anonymous):

lol idk i'm confused now maybe i am xD

OpenStudy (johnweldon1993):

lol well as we are going from -1 to 1...we are essentially getting smaller and smaller y-values....so the rate of change is actually negative...hence the -2 :)

OpenStudy (anonymous):

alright got it :P silly mistake!! thank you so much for ur time :)

OpenStudy (johnweldon1993):

Oh anything for you hun :)

OpenStudy (anonymous):

:)

OpenStudy (johnweldon1993):

So if you need anything else feel free to ask <3

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