find two numbers whose sum is 46 and whose product is a minimum
You want two numbers x and y such that x + y = 46 and we want to minimize xy. Since x + y = 46, we have y = 46 - x, so \[ xy = x \cdot \left( 46 - x \right) = 46x - x^2. \] So we want the value of x so that this expression is minimized. Do you know how to do this?
I understand how to do the equation, but I need a "minimized" answer, after you take the derivative you get the maximized answered of 23, how do you get the minimum ?
23^2?
is this the answer?
its telling me 23 is wrong
no 23^2=529
that is also wrong
23^2 wud lead to the greatest product
something like 45.9999999999 * 0.0000000001
thanks for trying everyone, im out
46 and 0 is
also wrong
is there a restriction like positive non negative integer solutions?
no zero allowed
oh then lets make the product negative
23 and 23 is a stationary point
23 and 23 is the maximum, i need the minimum
yes yes
calm your buns
LMAO Reported ^
bahaha
useless, most of you
question is wrong. see given any number x, you can get another smaller x satisfying x+y=46
oh i see
-inf * inf+46
makes sense
lox not inf, but tends to inf, this question was self made, not from any book
-inf * (inf+46)
just an argument to show why the product can be like -inf
first take -100,100+46, then take -1000000000 , 10000000000+46, it decreases without any boundary
just a waste of time, for an invalid question.
yes i just said this
i have a feeling the teacher meant to give bounds or something
@vivzchic22 did you get what i meant to say? first take x=-100, y=100+46, then take x=-1000, y=1000+46, .... then take x=-1000000000, y=1000000000+46, the product is not bounded, it decreases wihtout any boundary, hence no minimum value
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