Consider the function f(x) = x^4 - 32 x^2 + 3, \quad
-3

Question

Consider the function f(x) = x^4 - 32 x^2  + 3, \quad
 -3 <x < 9. This function has an absolute minimum value equal to  
and an absolute maximum value equal to

camper4834 · Answer

equal to what?

camper4834 · Answer

oh. thats the question

anonymous · Answer

Consider the function f(x) = x^4 - 32 x^2  + 3, \quad
 -3 (less than or equal to)  x (less than or equal to) 9. This function has an absolute minimum value equal to and an absolute maximum value equal to

camper4834 · Answer

the answer is solved by taking the derivative and setting it equal to 0

anonymous · Answer

its just asking for the maximum value and minimum value

anonymous · Answer

oh

anonymous · Answer

my bad read that wrong camper is right

camper4834 · Answer

partially right, the first derivative equal to 0 gives you the critical points!

camper4834 · Answer

if you want to know which one is the minimum and which one is the maximum you will also have to do the SECOND derivative

anonymous · Answer

just take the derivative and set it equal to zero, but you also have to test with the second derivative to see which is the max and which is the min

anonymous · Answer

I tried and it wont work

camper4834 · Answer

don't forget that there are probably multiple points that will give you zero but we only want the ones between -3 and 9

camper4834 · Answer

so tell me the derivative of f(x)