Question

PLEASE HELP!!!
How do I convert this equation into standard form? :(

Answer 1

:O :(

Answer 2

\[f(x)=2(x-11)^2+4\]

Answer 3

u wanna convert it to
\(f(x)=ax^2+bx+c\)

Answer 4

Yes QQ

Answer 5

ok first expand (x-11)^2

Answer 6

Would that be \[(x-11)(x-11)\]?

Answer 7

@ikram002p Thank you for helping me T^T I've asked this same question many times, all of which no one would respond to. :(

Answer 8

yeah continue :O

Answer 9

i asked lot of questions with no response as will :'(

Answer 10

I hate that :(

Answer 11

Okay, continuing after (x-11)(x-11) I got \[x^2-22x+121\]

Answer 12

good now multiply with 2 :)

Answer 13

another approach
vertex form a(x-h)^2 + k = 0
a = a = 2
h = -b/2a so -11 = -b/(2*2) gives b = -44
c = ah^2 + k = 2(11)^2 + 4 =

f(x) = 2x^2 -44x + 246

Answer 14

@ikram002p like this? \[2(x^2-22x+121)\]

Answer 15

And so I'd basically get triciaal's answer, once I multiply it by two?

Answer 16

yeah ,u would but after multiply u should add 4 to get the right answer :)

Answer 17

Add four? So \[f(x)=2x^2-44x+250\] is the answer?

Answer 18

little mistake :)
(2x^2-44x+242 )+4=(2x^2-44x+246 )

Answer 19

Ahhh XDD So \[2x^2-44x+246\] is the final answer? xD

Answer 20

yep :)

Answer 21

@triciaal Can you explain to me how you got that answer, though? I looked it over and I'm not really sure how you were able to figure it out >.< Like, I'm not sure how h = -b/2a and everything :(

Answer 22

I wonder if I could give you both medals... lol ^^

Answer 23

that is the vertex form
Can you do a new question on "how to convert (the answer above) to vertex form?
then I will go through the steps to work backwards to prove the original vertex form.

Answer 24

Okay ^^ xD