Question

Compute |v1| and |v2| where
v1=(2,-6) and
v2=(-4,7)

Answer 1

I assume that these are vectors?

Answer 2

Yes

Answer 3

if z is the vector z = <a,b>, then

|z| = sqrt(a^2 + b^2)

Answer 4

Remember that if \(\mathbf{v} = \langle a,b\rangle\), then \(\|\mathbf{v}\| = \sqrt{a^2+b^2}\).

Answer 5

So |v1| would be the square root of 40?

Answer 6

Correct. But I would simplify that.

Answer 7

Right. My thanks.

Answer 8

What do you get when you simplify \(\Large \sqrt{40}\)