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Mathematics 16 Online
OpenStudy (anonymous):

Please please help. I am trying to solve this problem and the answer is 145.58 but for some reason I am not getting that answer. (9000)[12+ (1/2)(60000/7200) + (1/900)(60000/7200)]

OpenStudy (anonymous):

give me a sec plz.

OpenStudy (anonymous):

thank you! i think I'm calculating the wrong numbers first

OpenStudy (anonymous):

Are you starting from the inside and working your way out?

OpenStudy (anonymous):

yes. I multiply (1/2)(60000/7200) first then i add 12. then i multiply (1/900)(60000/7200) and i add that value to my first value. then i multiply the number i get with 9000

OpenStudy (anonymous):

No.

OpenStudy (anonymous):

you do all multiplication first

OpenStudy (anonymous):

then addition

OpenStudy (anonymous):

then multiply what is on the outside by the inside total

OpenStudy (anonymous):

let me show u an example

OpenStudy (anonymous):

ok thank you an example would help:) ill try it right now again

OpenStudy (anonymous):

it will take a minute hold plz lol

OpenStudy (anonymous):

ok!

OpenStudy (anonymous):

-9[5(1/2)(2/3) + (3/4)(2/4)] here is the problem

OpenStudy (anonymous):

multiply 1/2 with 2/3

OpenStudy (anonymous):

(First)

OpenStudy (anonymous):

then: multiply 3/4 with 2/4

OpenStudy (anonymous):

you find the answers i will tell you the steps

OpenStudy (anonymous):

ok i will try it right now

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

can i do (1/2)*(2/3) in the calculator?

OpenStudy (anonymous):

yes i do that lol

OpenStudy (anonymous):

ok so i got .3333333333 and when i do (3/4)(2/4) i get .375

OpenStudy (anonymous):

okay found .33333... to the nearest tenth

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

add your answers together

OpenStudy (anonymous):

ok i get .7083333333

OpenStudy (anonymous):

round that to the nearest tenth

OpenStudy (anonymous):

then multiply that answer by 5. then finally multiply that total by -9 and you have you answer!

OpenStudy (anonymous):

ok i see what you're doing with that problem. When i try it with my problem i end up with 9000[12 + 4.166666667 + .0092592593] am i supposed to round those numbers before i multiply to 9000?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

then add them all up before you multiply the #s

OpenStudy (anonymous):

by 9000

OpenStudy (anonymous):

so would 4.16666... rounded be 4.167? and .0092592593 be .00926?

OpenStudy (anonymous):

what r u supposed to round to? do u know?

OpenStudy (anonymous):

or does it say anything about it?

OpenStudy (anonymous):

well the only thing i know is that 60000 is in ms and the answer is supposed to be in seconds

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

the answer is 145.58 seconds

OpenStudy (anonymous):

what does the entire problem say?

OpenStudy (anonymous):

The problem is a computer problem and we plug in those numbers according to a table that has the seek time, rotational delay, and track size. The numbers are all plugged in correctly in the formula which is Tavg= (# sectors)[Ts +(1/2)(1/r) + (1/s)(1/r). So the numbers I plug into that formula..

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

hold on

OpenStudy (anonymous):

lemme do it on paper

OpenStudy (anonymous):

The second one i'm supposed to calculate is (9000)[8 + (1/2)(60000/5400) + (1/750)(60000/5400)] and the answer is 122.13 seconds. I will try this one to see if I get the answer maybe my teachers answer to the first one is wrong

OpenStudy (anonymous):

ok thank you

OpenStudy (anonymous):

i get the answer 111,780

OpenStudy (anonymous):

from the first set of numbers

OpenStudy (anonymous):

@iambatman plz help?

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

sorry. I am not that great at math either... XD

OpenStudy (anonymous):

lol its ok thank you for helping anyway

OpenStudy (anonymous):

Np anytime!

OpenStudy (anonymous):

Good luck!

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

;) u r welcome

OpenStudy (anonymous):

@iambatman can you please please help me with this problem..

OpenStudy (anonymous):

just had to divide the answer by 1000:)

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