Question

Solve for x.
√6x+7+2x=3x
A. x=-1
B. x=7,-1
C. x=1
D. x=7

Answer 1

\[\sqrt{6x}+7+2x=3x\] is this your equation?

Answer 2

yes

Answer 3

It's best to split the square roots at the start,

\[\sqrt{6}\sqrt{x}+7+2x=3x\] now subtract 2x on both sides,

\[\sqrt{6}\sqrt{x}+7=3x-2x\] this would give us 1 x on the right side, now subtract the 7 on both sides,

\[\sqrt{6}\sqrt{x}=x-7\]

or really you don't have to split the square root but it's fine, now square both sides so you get,

\[6x=(x-7)^2 \implies 6x=x^2-14x+49\]

Answer 4

Now we get rid of the 6x
\[(x-10)^2=51 \implies x -10 = \pm \sqrt{51} \implies x = 10\pm \sqrt{51}\]

Answer 5

And this means none of your solutions are right because you probably gave me the wrong equation

Answer 6

oh yeah my bad the square root is over the 7 as well @iambatman

Answer 7

Well try it yourself now, it's basically the same process :)

Answer 8

See what you get and if you have trouble let me know.

Answer 9

ok

Answer 10

i got c

Answer 11

@iambatman

Answer 12

i have trouble @iambatman

Answer 13

Ok tell me how you got it..