The angular momentum of electron in an atom in its ground state for which n is equal to 1 is given by bohr formula n*h/4pi resulting in a finite value but when we calculate the same by the formula under root l*(l plus 1) *h/2pi where h/2pi is out of the root where l is orbital angular momentum of electron in the atom and its value is zero in the ground state leading to a zero orbital angular momentum in the ground state by the formula which is different than the value obtained by bohr formula so why this difference

Question

The angular momentum of electron in an atom in its ground state for which n is equal to   1   is given by bohr formula n*h/4pi resulting in a finite value but when we calculate the same by the formula  under root l*(l plus 1) *h/2pi          where h/2pi is out of the root  where l is orbital angular momentum of electron in the atom and its value is zero in the ground state leading to a zero orbital angular momentum in the ground state by the formula which is different than the value obtained by bohr formula   so why this difference

anonymous · Answer

beacause one is more mass

anonymous · Answer

The difference arises because, in respect of the angular momentum of the ground state of a single electron atom, the Bohr theory is wrong.
The Bohr theory was a faltering step on the road to quantum mechanics - quantum mechanics correctly predicts zero orbital angular momentum for the ground state of a single electron atom.