Find area of region inside r = 2+2cos(theta) and rsin(theta) = 3/2

Question

vlery · Answer

if you're looking for theta there's no solution

catlover5925 · Answer

I don't know what type of math u are in but I have never learned this and im a sophmore in an advanced math class...sorry wish I could help

anonymous · Answer

$$3 /(2\sin \theta) = 2+2\sin \theta$$

anonymous · Answer

there is one solution
48.6

anonymous · Answer

The equation  
$$
r \sin(\theta) =\frac 3 2\
y=\frac 3 2
$$
is a line parallel to the x-axis
I do not know what you mean by the are inside a  line and a cardioid.

anonymous · Answer

by the area

jhannybean · Answer

Area f a region that is bound by polar coordinates: $A = \dfrac{1}{2}r^2 \theta$ 

Therefore the area of a olar region is: $A = \int_a^b \dfrac{1}{2}r^2d\theta$

fibonaccichick666 · Answer

Since no one has said this, just draw a picture to start.  It makes life A LOT easier.  I am assuming this is calcI/II and you have just studied integration as pointed out by jhanny.  So, start by graphing.