Triangle XYZ is located at X (-2, 1), Y (-4, -3), and Z (0, -2). The triangle is then transformed using the rule (x-1, y+3) to form the image X'Y'Z'. What are the new coordinates of X', Y', and Z'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.
@uri @bibby
@iGreen
Subtract the x-values by 1, and add the y-values by 3.
X = (-2, 1) Y = (-4, -3) Z = (0, -2) X' = (-2 - 1, 1 + 3) Y' = (-4 - 1, -3 + 3) Z' = (0 - 1, -2 + 3) Can you simplify those? @coolaidpower
X'=(-1, 4) Y'= ( -5, -6) Z' ( 1, 1) is that it? @iGreen
-2 - 1 isn't -1 -3 + 3 isn't -6 0 - 1 isn't 1 Check those over
ok
@iGreen
X'= (-3, 4) Y'=(-5, 0) Z'=(-1,1 ? @iGreen
Yep, that's your answer!
Welcome to Open Study! You can give medals by clicking 'Best Response'. @coolaidpower
lol @iGreen i know xD
Okay, lol.
thank you btw @iGreen
Oh real quick @iGreen it says "Describe what characteristics you would find if the corresponding vertices were connected with line segments". what should i do here?
Oh, it's asking what you would find if you connected X with X', Y with Y', and Z with Z'. Hold on let me graph it for you.
ok
Just say when you connect them the lines will be parallel. I g2g, bye
ok thank you @iGreen
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