If this reaction produced 32.5 g of KCl, how much O2 was produced (in grams)?
When heated, KClO3 decomposes into KCl and O2.
What have you tried so far to solve the problem?
converted g to moles of KCl. Got stuck after that. Not solid on converting moles of KCl to moles of O2
@surry99
ok in chemistry you should always start with a balanced chemical rxn...so do that for me please
Hint: KCl03----> KCl + 02 Now you need to balance this equation
2KClO3 ----> 2KCl + 3O2
Good...now for every 2 moles of KCl produced, how many moles of O2 were produced?
3?
Yes,,,so how many moles of KCl do you have?
2
no... 32.5 g of KCl was produced...how many moles is that?
32.5g x 1 mol KCl/74.54g KCl= 0.436 mol KCl ?
ok...so now how many moles of 02 were produced.
This is where I get confused. I use 0.436 mol KCl but idk what goes next. I know I need g on top & moles on bottom but I'm not sure which way to set it up
Ah...just write in the units and you will get it correct... .436 mol of KCl * 3 moles of O2/2 moles of KCl = ? What happens to the units of moles of KCl when you multiply?
They cancel out, which gives you 0.654 mol O2
but i still need to find g... so I use molar mass?
Exactly use the molar mass of O2 Excellent....always write in your units and that way you can check to see if the mole ration is correct!!
Ok. You help out a lot. Thank you so much.
your welcome.
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