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Chemistry 22 Online
OpenStudy (anonymous):

If this reaction produced 32.5 g of KCl, how much O2 was produced (in grams)?

OpenStudy (anonymous):

When heated, KClO3 decomposes into KCl and O2.

OpenStudy (surry99):

What have you tried so far to solve the problem?

OpenStudy (anonymous):

converted g to moles of KCl. Got stuck after that. Not solid on converting moles of KCl to moles of O2

OpenStudy (anonymous):

@surry99

OpenStudy (surry99):

ok in chemistry you should always start with a balanced chemical rxn...so do that for me please

OpenStudy (surry99):

Hint: KCl03----> KCl + 02 Now you need to balance this equation

OpenStudy (anonymous):

2KClO3 ----> 2KCl + 3O2

OpenStudy (surry99):

Good...now for every 2 moles of KCl produced, how many moles of O2 were produced?

OpenStudy (anonymous):

3?

OpenStudy (surry99):

Yes,,,so how many moles of KCl do you have?

OpenStudy (anonymous):

2

OpenStudy (surry99):

no... 32.5 g of KCl was produced...how many moles is that?

OpenStudy (anonymous):

32.5g x 1 mol KCl/74.54g KCl= 0.436 mol KCl ?

OpenStudy (surry99):

ok...so now how many moles of 02 were produced.

OpenStudy (anonymous):

This is where I get confused. I use 0.436 mol KCl but idk what goes next. I know I need g on top & moles on bottom but I'm not sure which way to set it up

OpenStudy (surry99):

Ah...just write in the units and you will get it correct... .436 mol of KCl * 3 moles of O2/2 moles of KCl = ? What happens to the units of moles of KCl when you multiply?

OpenStudy (anonymous):

They cancel out, which gives you 0.654 mol O2

OpenStudy (anonymous):

but i still need to find g... so I use molar mass?

OpenStudy (surry99):

Exactly use the molar mass of O2 Excellent....always write in your units and that way you can check to see if the mole ration is correct!!

OpenStudy (anonymous):

Ok. You help out a lot. Thank you so much.

OpenStudy (surry99):

your welcome.

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