Ask your own question, for FREE!
Physics 18 Online
OpenStudy (anonymous):

Two large books are stacked on top of each other on a table . The mass of each book is 6.5Kg Given that the coefficient of static friction between bottom book and table is 0.15, what is the lowest the coefficient of static friction between the books can be in order to apply force and move both books?

OpenStudy (anonymous):

Answer in textbook is 0.30

OpenStudy (anonymous):

so you want to know how to do this right?

OpenStudy (anonymous):

yes but please consider that this is a gr.11 physics problem

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

multiply the force of the object perpendicular to the surfis by the coefficient of friction is the frictional force and i'm in 7th grade i think i can cope maby

OpenStudy (anonymous):

Yes I can conclude that a long time ago, but I want the process and why is that the process. Thanks for trying though

OpenStudy (anonymous):

now can i have a medal please

OpenStudy (anonymous):

ok sorry i had some lagg and did not see your messege

OpenStudy (anonymous):

np

OpenStudy (anonymous):

because the bumps of the object determen the coefficient of friction...

OpenStudy (anonymous):

i have to go in a min

OpenStudy (anonymous):

could you demonstrate what you said mathematically please ? thanks

OpenStudy (anonymous):

do u want me to explain it to you or have you figured it out?

OpenStudy (anonymous):

yes please explain it to me

OpenStudy (anonymous):

its difficult to type it. ill just solve it and post a picture of it.

OpenStudy (anonymous):

sure np

OpenStudy (anonymous):

is the answer 0.3?

OpenStudy (anonymous):

yes, the textbook says that

OpenStudy (anonymous):

alright. so for minimum coefficient, we need to make an assumption that its going to be going at a constant velocity

OpenStudy (anonymous):

in other words, the force applied will be equal to Fmax

OpenStudy (anonymous):

and acceleration 0

OpenStudy (anonymous):

now, for the upper book to move together, it should have the same constant velocity

OpenStudy (anonymous):

which means that the friction on upper book equals friction on lower book

OpenStudy (anonymous):

which if you solve will give the coefficient

OpenStudy (anonymous):

so, 0.15*13g=u*6.5g. will give u=0.3

OpenStudy (anonymous):

ahaa ok ! I see now where I was wrong before in my trials. Thanks a lot :D

OpenStudy (anonymous):

hey are you there?

OpenStudy (anonymous):

is the force given?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

so in the fed of the top book what horizontal forces do u think will be present?

OpenStudy (anonymous):

only friction right?

OpenStudy (anonymous):

if there was only friction, wouldn't the upper block accelerate?

OpenStudy (anonymous):

No, I am assuming that some sort of force acted on it horizontally. At the end, I figured out the answer in a different approach than yours. Thanks anyways :)

OpenStudy (anonymous):

what did u do?

OpenStudy (anonymous):

or rather, how did you do it?

OpenStudy (anonymous):

I will answer you later :) , I have a test tomorrow that I am studying for tomorrow.

OpenStudy (anonymous):

oh sorry for disturbing

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!