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OpenStudy (anonymous):
what is the 7th and 10th term in this situation
an=2+(n-1)3
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OpenStudy (anonymous):
please help
OpenStudy (anonymous):
is this really
\[a_n=2+(n-1)^3\] or
\[a_n=2+(n-1)\times 3\]?
OpenStudy (anonymous):
that is it
OpenStudy (anonymous):
there are two different expressions
which one is it?
OpenStudy (anonymous):
the 2nd one
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OpenStudy (anonymous):
Since \[
a_n = 2+(n-1)\cdot 3
\]We can say the 7th term, \(a_7\) is: \[
a_7 = 2+(7-1)\cdot 3
\]
OpenStudy (anonymous):
where you see an \(n\) replace it by \(7\) and get what @wio wrote above
OpenStudy (anonymous):
But they will want you to simplify.
OpenStudy (anonymous):
wait so wio are you correct?
OpenStudy (anonymous):
thx
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OpenStudy (anonymous):
wats the 10th
OpenStudy (anonymous):
What I gave you is how to find the solution, you still have to do the math to simplify.
OpenStudy (anonymous):
The 10th term can be found with the same pattern.
OpenStudy (anonymous):
\[
a_{\#} =2+(\#-1)\cdot 3
\]
OpenStudy (anonymous):
wat do i have to do now simplify?
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OpenStudy (anonymous):
For example: \[
2+(7-1)\cdot 3 = 2+ (6)\cdot 3
\]
OpenStudy (anonymous):
thanx but this too hard
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