I now just need help finding the upper range of the below equation. I have the domain as (-3,3) and the range [2/(sqrrt(3), ?????] thanks for the help!! Please help me find the domain and range of : y=2/(4th root(9-x^2)
Domain is first number and range would be the second number. so just find the x and y
which part are you stuck at
having even roots in a problem you will have some restrictions if the thing inside is less than 0 also having fractions can be a problem because we don't want to divide by 0 you need to make sure the thing inside your 4th root there is positive
so is the domain -3 to 3?
but not including 3?
sounds good not including either -3 or 3
so then do you put -3 and 3 into the equation to get the range limits?
but then that would give you zeros for the denominator so what then?
what happens when you take 1 and divide it by numbers that get really really close to 0?
like what is 1/.00001 equal to? is that actually a big number?
yeah infinity
and we restricted our domain so that the function exists over the real numbers we basically have a positive divided by a positive so we know that are range will exist only for positive numbers and it actually goes to infinity but we also need to figure out the lowest y value
the thing will be the smallest if you replace x with 0 and solve for y
that would be 2/(4th rt(9) - our teacher makes us do specific answers, no decimals
so that is the low end of our range
you could simplify that though
so the top end would be when x is close to 3 but not 3?
\[\sqrt[4]{9}=\sqrt[4]{3^2}=3^\frac{2}{4}=?\]
sorry my computer kicked me off
I am not sure, I see how you got to that point though
oh duh, are you just saying 3^1/2?
so 2/sqrt(3)?
well yeah that would be the smallest of the range
and then you noticed that if you plug in either endpoint the bottom was getting closer to zero therefore the fraction was getting positive large
so do you what the range is?
also you weren't the only one having problems i couldn't get openstudy to load for like 5 to 6 minutes
Any help on the upper part of the range? I get that x=0 at the low end, and x should = 3 at the upper end, but 3 cannot be included, so it is a number infanetly close to three and i can't wrap my brain around that?
emily we already got the upper part
and the domain doesn't include -3 or 3, but would the range include both numbers? I feel like it should include them?
remember you said the the function was getting huge as our x's approaches x=3 or x=-3
the domain is (-3,3)
the range is [2/sqrt(3),inf) because the smallest was 2/sqrt(3) and because the function got huge when the bottom went to 0
got positive huge*
emily do you understand?
Oh wow, yeah duh, it would be infinity wouldnt it? Thanks!
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