Pleaseee Helpppp What is the simplified form of the seventh root of x times the seventh root of x times the seventh root of x times the seventh root of x?
\[\sqrt[7]{x} *\sqrt[7]{x}*\sqrt[7]{x} *\sqrt[7]{x} = x ^{1/7}*x ^{1/7}*x ^{1/7}*x ^{1/7}\] \[x ^{1/7}*x ^{1/7}*x ^{1/7}*x ^{1/7} = x^{1/7+1/7+1/7+1/7}\]
Thankss, could you help me with some more questions?
sure
Frank and Gertrude mow lawns for extra money over the summer. Frank's income is determined by f(x) = 5x + 15, where x is the number of hours. Gertrude's income is g(x) = 4x + 20. If Frank and Gertrude were to combine their efforts, their income would be h(x) = f(x) + g(x). Assume Frank works 4 hours. Create the function h(x), and indicate if Frank will make more money working alone or by teaming with Gertrude. h(x) = x + 5, work alone h(x) = x + 5, team with Gertrude h(x) = 9x + 35, work alone h(x) = 9x + 35, team with Gertrude
f(x) = 5x + 15, g(x) = 4x + 20 h(x) = f(x) + g(x) h(x) =???
I'm confused
in which part?
5x+15+4x+20 right?
right. join the same variables
9x+35 Right?
correct
now if x = 4 where do you think frank will earn more? in f(x) or in h(x)
h(x)
correct. and when will he earn more if he is working with Gertrude, where he has to share the earnings, or if he is working alone.
With Gertrude and 35?
@sangya21 ?
I think alone cause if with Gertrude, he will get 35.1 and alone he will get 71 9*4 +35 = 36+35 = 71
h(x) = 9x + 35, work alone so that's the answer?
I think so.
Okayy, I'm going to go with that.
What is the 1st term when 1 + 6x2 + 5x4 + 3x3 is arranged in descending order? Could you help with this one?
is this addition sign between them?
Yeah I think
5x^4 + 3x^3 + 6x^2 +1 if x is positive and reverse the above eq. id x is -ve
What?
when x is +ve, the number increases with increase in power and when x is -ve, the number decreases with increase in power
What is +ve and -ve?
Positive and negative
Oh okay
These are the answer choices 1 6x2 5x4 3x3
5x^4 + 3x^3 + 6x^2 +1 lets consider x is positive
I'm not sure
why?
I can suggest someone else for you then .
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