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Mathematics 15 Online
OpenStudy (anonymous):

Determine which relation is a function. A. {(–5, 1), (–5, 0), (–2, 1), (–1, 4), (6, 2)} B. {(–5, 1), (–2, 0), (–2, 2), (3, 4), (6, 2)} C. {(–5, 1), (–2, 0), (–1, 1), (2, 4), (6, 3)} D. {(–5, 3), (–2, 0), (–1, 2), (6, 4), (6, 3)} how would i do this

OpenStudy (ccswims):

In order for a relation to be a function all domains (or x-axis) must NEVER repeat

OpenStudy (ccswims):

So which one of these examples DON'T have repeating numbers?

OpenStudy (anonymous):

d

OpenStudy (ccswims):

D has 2 "6"s

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

c?

OpenStudy (ccswims):

Yes!

OpenStudy (anonymous):

could you explain to me a little more about functions

OpenStudy (ccswims):

ok, for example Take the coordinates (2, 3). We know it as 2 = x-axis and 3 = y-axis A relation is basically just giving the x and y axis and different name x-axis = domain and y-axis = range

OpenStudy (ccswims):

And in order for a relation to be a function it must NEVER have a repeating domain

OpenStudy (ccswims):

BUT, don't get confused with range (or y-axis). A range can have repeating numbers, just not the domain

OpenStudy (anonymous):

For a function, no member of the domain set can map to more than one member of the range set. i.e. there cannot exist(a,b) and (a,c) when b and c are different. This rule is sufficient

OpenStudy (ccswims):

Like I said though, the range can have repeating numbers

OpenStudy (anonymous):

ooh okay i see

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