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just to check my math, cos pi/10 = .95 sin pi/10 =.31
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\[[\frac{ 1 }{ 4 }(\cos \frac{ \pi }{ 10 }+i \sin \frac{ \pi }{ 10 })]^{5}\]
there is a theorem we can use
( r cos theta + i sin theta ) ^n = r^n * cos (theta*n ) + i sin (thetan * n )
i found something like this, \[\frac{ 1 }{ 4 }^{5}(\cos (5*\frac{ \pi }{10}+i \sin (5*\frac{ \pi }{ 10 })\]
yes thats right
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here is my findings, .000976(.000796)+i(.999)
what is cos(pi/2) ?
cos (5pi/10) = cos(pi/2) = 0
where did cos(pi/2)come from
5pi/10 = pi/2
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so disregard my last equation, \[\frac{ 1 }{ 4 }^{5}(\cos \frac{ \pi }{ 2}+isin \frac{ \pi }{ 2 })\]
\[\frac{ 1 }{ 4 }^{5}(0+i*1)\]
final answer would be \[\frac{ 1 }{1024 }i\]
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