Question

lim x->0 sin3x sin5x/x^2

Answer 1

\[\sin (3x)\sin(5x) = \frac{\cos(2x) - \cos(8x)}{2}\]

Answer 2

Or just use L'Hospital's.

Answer 3

ah oh okay got it thank you

Answer 4

:)

Answer 5

you can also separate that x^2=x*x
then multiply and divide by 3 as well as 5
then you have the usual limit sinx/x at zero
which is 1
and the numbers that you multiplied by are what remains