Given a soda can with a volume of 36 and a diameter of 4, what is the volume of a cone that fits perfectly inside the soda can?
volume of the can = pi r^2h = 36 r = 1/2 * 4 = 2 so 36 = pi*2^2 * h h = 36 / 4 pi
given that volume of the cone thet fits into the can = (1/3) pi r^2 h can you find this volume? h = 36/4pi = 9/pi and r = 2
2.9
oh - there was no need for me to do all this!!
9/pi is 2.9 when rounded to the nearest tenth
and thank you so much!
as the volume of the cone = 1/3 * volume of the cylinder the answer is 1/3 * 36 = 12
so the final answer would be 12?
yes - there was no need to do all those calculations!! - the volume of the cone is 1/3 times the volume of the cylinder
V can = pi r^2 h V cone = (1/3 pi r^2 h r and h is the same for both can and cone
I don't know why I didn't see that in the first place!!
do you follow what wrote?
its not 2.9 9/pi is the height of the the can ( and the cone)
okay, the final answer is 12
I think. Haha
if we substitute h = 9/pi into the formula for the volume of the cone we get 12 which confirms the result
Okay. Thank you so much! (:
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