indices= simplify 9^1 and a 1/2
pls help

Question

indices= simplify 9^1 and a 1/2
pls help

anonymous · Answer

@Linchpin 
@confluxepic 
@TheSmartOne

confluxepic · Answer

They are simplified.

confluxepic · Answer

You can't further simplify 1/2.

confluxepic · Answer

Oh. Wait. Indices.

campbell_st · Answer

rewrite the power as an improper fraction

$$9^{\frac{3}{2}}$$

and rewrite 9 as a power of 3

then use the power of a power law... multiply the powers

$$(3^2)^{\frac{3}{2}} = 3^{\frac{3}{2} \times 2}$$

and simplify

anonymous · Answer

does it equal to 9 over 2??

anonymous · Answer

is the final answer 9
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                             2           @campbell_st

campbell_st · Answer

I'm not sure... as I've answered this question 

simplify 

$$9^{~1\frac{1}{2}}$$

if thats the question you need to simplify 

$$3^{\frac{3}{2} \times 2}$$

anonymous · Answer

@campbell_st would the answer be 27?

campbell_st · Answer

that's correct