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indices= simplify 9^1 and a 1/2 pls help
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@Linchpin @confluxepic @TheSmartOne
They are simplified.
You can't further simplify 1/2.
Oh. Wait. Indices.
rewrite the power as an improper fraction \[9^{\frac{3}{2}}\] and rewrite 9 as a power of 3 then use the power of a power law... multiply the powers \[(3^2)^{\frac{3}{2}} = 3^{\frac{3}{2} \times 2}\] and simplify
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does it equal to 9 over 2??
is the final answer 9 --- 2 @campbell_st
I'm not sure... as I've answered this question simplify \[9^{~1\frac{1}{2}}\] if thats the question you need to simplify \[3^{\frac{3}{2} \times 2}\]
@campbell_st would the answer be 27?
that's correct
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