A particle moves along the x-axis so that at any time t, measured in seconds, its position is given by s(t) = sin(t) − 4cos(2t), measured in feet. What is the acceleration of the particle at time t = π seconds?

Numerical Answers Expected!

Question

A particle moves along the x-axis so that at any time t, measured in seconds, its position is given by s(t) = sin(t) − 4cos(2t), measured in feet. What is the acceleration of the particle at time t = π seconds?

Numerical Answers Expected!

jhannybean · Answer

$$\ \int s(t) dt = v(t)+c$$$$\ \int [v(t) + c]dt = a(t) +ct +d$$

anonymous · Answer

So what do I get as the answer ? :)

jhannybean · Answer

So you have to integrate the position function twice to get the acceleration function when t = $\ \pi$

jhannybean · Answer

can you integrate the position function and tell me what you get?

anonymous · Answer

I'm not sure how I'm in a rush so you can give me the answer and then explain it because I have a limited amount of time to submit the work :P
Thanks :)

jhannybean · Answer

Is this a test you are working on, or homework?

anonymous · Answer

pop quiz

jhannybean · Answer

It's against Openstudy code of conduct for me to give you answers. I am sorry.

anonymous · Answer

okay then can u please explain it as fast as u can ?

jhannybean · Answer

If you work with me on the problem then I can help you :)

anonymous · Answer

ok :) how do i start

jhannybean · Answer

Yeah, you integrate both functions to get the function of acceleration, then plug in t = pi, solve for your constant (i.e c, d, e ,f, etc...) and once you get the value of your constant, plug it back into the equation for acceleration and you're set.

anonymous · Answer

so what do i get as a result ?: )

anonymous · Answer

i got the answer as 0