Question

solve. 1/3(x-2) + 1/2(x+3) = 1/4(3x+1)

Answer 1

do i get common denominators first or distribute. need help thnx

Answer 2

I would get common denominators first, then distribute.

Answer 3

waitt i got got common denominators and then 2(6x-12)+3(3x+9) =1/4(3x=1)

Answer 4

\[\frac{ 1 }{ 3(x-2) }+\frac{ 1}{ 2(x+3) }= \frac{ 1 }{ 4(3x+1) }\]

Answer 5

i got something else.
your common denominar should be 3(x-2)(X+3)(4)(3x+1)

Answer 6

this is so ugly.

so you know x doesnt equal 2,-3, and -1/3

and you have
4(x+3)(3x+1) + 3(2)(x-2)(3x+1) = 3(x-2)(x+3)
after you multiply both sides by the denominator

Answer 7

oh ok

Answer 8

now to distribute and simpllify.
do you want to try it?

Answer 9

yea i will write it down and look it over

Answer 10

these equations really mess w/ u

Answer 11

yea. they are really long. too much numbers= confusing.

we could compare answers when you're done

Answer 12

why was the 2 not in the common denominator
with 3 and 4

Answer 13

because 4 is 2x2

Answer 14

oh ok i see

Answer 15

did you copy the equation right?
because i got even uglier answers

Answer 16

I putting in in the common denominators

Answer 17

do I distribute and then factor it

Answer 18

i think you should distribute and then simlify.

if you factor, you would undo your distribution

Answer 19

did you get the right answer

Answer 20

you have the answers?

Answer 21

in a moment

Answer 22

did you get 18^2-28x-12 after all of that distributing

Answer 23

and combining

Answer 24

no. i got 27x^2 +7x -2

either or both of us might have made a mistake.

Answer 25

I saw that you added put in a 2 with the rest of factors

Answer 26

and you have
4(x+3)(3x+1) + 3(2)(x-2)(3x+1) = 3(x-2)(x+3)
after you multiply both sides by the denominator

Answer 27

was puttign in a (2) w/ the (x-2)(3x+1)

Answer 28

a mistake

Answer 29

no. you need to multiply by 2.
because i didnt multiply by4 to it.
to get the 4 , i multiplied the 2 by 2 to get get.
that why i didnt multiply by 2 with the last term