Question

To the nearest degree, the measure of angle Q is

Answer 1

looks like a job for the law of cosines

Answer 2

do you know it?

Answer 3

no i dnt understand how to solve this with cosines

Answer 4

I took notes, but I dnt know how they would get there answer for the steps.

Answer 5

ok we can do it

Answer 6

the easiest thing to remember is
\[a^2=b^2+c^2-bc\cos(A)\] because the first part looks just like pythagoras

Answer 7

but that is for solving for one side
if you want an angle you have to solve the above eqation and get
\[\cos(A)=\frac{b^2+c^2-a^2}{2bc}\]

Answer 8

that makes
\[\cos(Q)=\frac{9.4^2+6.2^2-8.8^2}{2\times 9.4\times 6.2}\]

Answer 9

evidently you want to use a calculator
after that, you have the cosine of Q, to find Q, take the arccosine of that number

Answer 10

Do I solve it like this..
cos(Q)= 49.36/116.56
\[\cos^{-1} (.42) = 65.2\] ?

Answer 11

Or am I wrong ? @satellite73 sorry if I did that wrong