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Mathematics 14 Online
OpenStudy (anonymous):

find the equation of the tangent line y=2tan^3x at (pi/4,2)

OpenStudy (mathmale):

You might find this problem to be slightly easier to understand and solve if you'd write the function in this manner:\[y=\tan^3 x~or~y=(\tan x)^3\]

OpenStudy (mathmale):

To find the equation of the tangent line to the graph of this function, you'll need the derivative, dy/dx, because here the derivative value is the value of the slope of the tangent line to the curve at any x for which this derivative is defined.

OpenStudy (anonymous):

yeah but i need help finding the derivative

OpenStudy (anonymous):

use chain rule, which makes the derivative \[(2\sec ^{2}3x)(3)\]

OpenStudy (anonymous):

\[6\sec ^{2}3x\]

OpenStudy (anonymous):

i believe

OpenStudy (anonymous):

sorry i was really late in replying

OpenStudy (anonymous):

but i hope this helps

OpenStudy (anonymous):

its okay thank you. can you help me with the finding the slope

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