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find the equation of the tangent line y=2tan^3x at (pi/4,2)
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You might find this problem to be slightly easier to understand and solve if you'd write the function in this manner:\[y=\tan^3 x~or~y=(\tan x)^3\]
To find the equation of the tangent line to the graph of this function, you'll need the derivative, dy/dx, because here the derivative value is the value of the slope of the tangent line to the curve at any x for which this derivative is defined.
yeah but i need help finding the derivative
use chain rule, which makes the derivative \[(2\sec ^{2}3x)(3)\]
\[6\sec ^{2}3x\]
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i believe
sorry i was really late in replying
but i hope this helps
its okay thank you. can you help me with the finding the slope
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