Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (demonchild99):

Which transformation will map figure H onto figure H'? Two congruent hexagons figure H and figure H prime are drawn on a coordinate grid. Figure H has vertices at 4, 2, 7, 3, 7, 6, 4, 7, 2, 6 and 2, 3. Figure H prime has vertices at 4, negative 8, 7, negative 7, 7, negative 4, 4, negative 3, 2, negative 4 and 2, negative 7 Reflection across the y-axis Vertical translation of 10 units Vertical translation of 15 units Reflection across the axis

OpenStudy (demonchild99):

OpenStudy (anonymous):

hold on @I_Need_Help_With_Home

OpenStudy (anonymous):

It should be vertical translation of 10 units. @demonchild99

OpenStudy (demonchild99):

ok....do you think you can help me with a few more?

OpenStudy (anonymous):

Sure

OpenStudy (anonymous):

Thanks @I_Need_Help_With_Home for your help u get a medal

OpenStudy (demonchild99):

i am like so frazzed out because i have to get all my work turned in today...and i would give you a medal but i dont know how to yet....lol

OpenStudy (anonymous):

@demonchild99 do u see best Response click on it to give medals lol

OpenStudy (demonchild99):

Eric reflected parallelogram ABCD across the x-axis. If angle A is 125° and angle B is 55°, what is the degree measurement of angle A'? 55°, 180°, 70°, 125°

OpenStudy (anonymous):

@I_Need_Help_With_Home

OpenStudy (anonymous):

I don't know the answer @demonchild99

OpenStudy (demonchild99):

oh...um...ok can you try another..

OpenStudy (anonymous):

Yeah sure

OpenStudy (demonchild99):

Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV. Rectangle JKLM is drawn on the grid with vertices J at negative 7, negative 6. K is at negative 4, negative 6). L is at negative 4, negative 2. M is at negative 7, negative 2. Rectangle J prime K prime L prime M prime is drawn with vertices J at prime 6, negative 9. K prime is at 9, negative 9. L prime 9, negative 5. M prime is at 6, negative 5. Trapezoid STUV is drawn with vertices at S 3, 2. T is at 5, 5. U is at 2, 6. V is at 1, 4. What will be the location of T' in the image trapezoid S'T'U'V'? (18, -2) (18, 2) (15, -2) (15, 2)

OpenStudy (demonchild99):

OpenStudy (anonymous):

What do you think it is?

OpenStudy (demonchild99):

i think it is the third one

OpenStudy (anonymous):

Can you explain why you think it is?

OpenStudy (demonchild99):

not really all the numbers are kinda confusing me....i always have problems with numbers....

OpenStudy (anonymous):

you add 13 to the x coordinate of T and subtract 3 from the y coordinate of T so what would the expression be now?

OpenStudy (demonchild99):

it would be the second one

OpenStudy (anonymous):

Correct (5+13),(5-3) = (18,2)

OpenStudy (demonchild99):

yay!....i dont like math and it dont like me....

OpenStudy (anonymous):

Lol

OpenStudy (demonchild99):

Triangle HAM is translated using the rule (x,y)→(x+6, y) to create triangle H'A'M'. If a line segment is drawn from point H to point H' and from point A to point A', which statement would best describe the line segments drawn? They share the same midpoints. They are parallel and congruent. They are diameters of concentric circles. They are perpendicular to each other.

OpenStudy (anonymous):

What do you think the answer is and why

OpenStudy (demonchild99):

im not sure i dont really understand what its really asking

OpenStudy (anonymous):

Like ummm what is your best guess at this question and why u guess it

OpenStudy (anonymous):

okay so you would move the triangle HAM to the right 6 units because of the "x+6"

OpenStudy (demonchild99):

mkay i understand that part

OpenStudy (anonymous):

So after what I just said what do you think it is now?

OpenStudy (demonchild99):

they are parrelell and congruent

OpenStudy (anonymous):

Correct :)

OpenStudy (demonchild99):

yay!

OpenStudy (anonymous):

Do you have any other questions?

OpenStudy (demonchild99):

yeah....hold on...,thank you so much you r a life saver

OpenStudy (anonymous):

Your welcome :)

OpenStudy (demonchild99):

The triangle PQR shown on the coordinate grid below is reflected once to map onto triangle P'Q'R': Triangle PQR drawn on a 4 quadrant coordinate grid with vertices P is at 7, 6. R is at 5, 2. Q is at 3, 5. If vertex P' is at (7, -6), what are the coordinates of vertex R'? (5, -3) (3, -5) (3, -2) (5, -2)

OpenStudy (demonchild99):

i think it is the last one (5,-2)

OpenStudy (anonymous):

I think it is too

OpenStudy (demonchild99):

What set of reflections would carry kite ABCD onto itself? Kite ABCD is shown. A is at negative 7, 2. B is at negative 5, 3. C is at negative 2, 2. D is at negative 5, 1. x-axis, y=x, y-axis, x-axis y-axis, x-axis, y-axis, x-axis y=x, axis, x-axis x-axis, y-axis, x-axis

OpenStudy (anonymous):

First of all do you understand what it means to reflect something over an axis?

OpenStudy (demonchild99):

um yes ma'am....

OpenStudy (anonymous):

Okay. Well the way I think about it is almost like when you look at your reflection in the water... Your image is opposite what you actually look like... it is the same with this... when you reflect something over an axis you essentially flip it...

OpenStudy (demonchild99):

mkay.....i was kinda thinking the answer would be the last one but i wasnt sure?

OpenStudy (anonymous):

Yes correct, and sorry I really didn't know how to explain it

OpenStudy (demonchild99):

so it would be x-axis y-axis x-axis?

OpenStudy (anonymous):

Yes

OpenStudy (demonchild99):

ok...cool.....i think i have a couple more...if its not to much...i really appreciate you helping me

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

I would love to help you with more questions, I like helping people

OpenStudy (demonchild99):

wait i think it would be the second choice for the last one..

OpenStudy (anonymous):

Why do you think that?

OpenStudy (demonchild99):

because if i do it in my head you flip it over y then x then y and then x again it lands in the same spot it started right?

OpenStudy (demonchild99):

thats what im supposed to do right?

OpenStudy (anonymous):

What do you mean y then x then y then x don't make it to the same spot because x isn't the same as y, It would make it to the same spot if you did y then x then y then x then y

OpenStudy (demonchild99):

but if i flip it over the y-axis and x-axis then the y-axis and x-axis again it goes in a counterclockwise circle almost....putting it right back where it started

OpenStudy (anonymous):

Oh I see, I think you are right. @The_Jokers_wife what do you think?

OpenStudy (demonchild99):

i have three more questions

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

And that means what @I_Need_Help_With_Home

OpenStudy (demonchild99):

Trapezoid ABCD is rotated 180 degrees about the origin and then reflected over the x-axis, followed by a reflection over the y-axis. What is the location of point A after the transformations are complete? Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1. (5, -1) (-5, -1) (5, 1) (-5, 1)

OpenStudy (anonymous):

Nvm @The_Jokers_wife

OpenStudy (demonchild99):

wrong file hold up...lol

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

Lol XD kk

OpenStudy (demonchild99):

OpenStudy (anonymous):

Think of it like this, 180 rotation wud take that point to 4th quadrant reflection in x-axis takes that to 1st quadrant reflection in y-axis brings it back to 2nd quadrant again. So, the sequence of transformations will bring A back to where it started

OpenStudy (demonchild99):

ohhh so the answer would be c

OpenStudy (anonymous):

Correct

OpenStudy (demonchild99):

D

OpenStudy (demonchild99):

it says negative

OpenStudy (anonymous):

A was originally at (-5, 1) right? then 180 degree rotation puts it at (5,-1) then the x-axis flip makes it (5, 1)

OpenStudy (demonchild99):

Figure EFGH on the grid below represents a trapezoidal plate at its starting position on a rotating surface: A trapezoid EFGH drawn on a 4 quadrant coordinate grid with vertices at E negative 4, 8. F is at negative 7, 5. G is at negative 4, 3. H is at negative 2, 5. The plate is rotated 90° about the origin in the counterclockwise direction. In the image trapezoid, what are the coordinates of the endpoints of the side congruent to side EF? (-8, -4) and (-5, -7) (-8, -4) and (-5, -2) (4, -8) and (2, -5) (4, -8) and (7, -5)

OpenStudy (demonchild99):

and ohhh ok....so the answer really is c

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

For the question you just asked; 90 degree rotation :- (x, y) --> (-y, x) take a look at graph, can u tell coordinates of G ?

OpenStudy (demonchild99):

-4 and 3...right?

OpenStudy (anonymous):

Correct, now apply the transformation

OpenStudy (anonymous):

(x, y) --> (-y, x) (-4, 3) --> ?

OpenStudy (demonchild99):

-3 and 4

OpenStudy (anonymous):

nope try again

OpenStudy (anonymous):

(x, y) --> (-y, x) (-4, 3) --> (-3, -4) Dont just change the 4 to a positive just cause it switched

OpenStudy (demonchild99):

oh....my bad...i think thats why i always got problems like these wrong.....if i dint see a - sign i made it possitive {forehead smack}

OpenStudy (anonymous):

Lol

OpenStudy (demonchild99):

so what do i do after you get that equation?

OpenStudy (anonymous):

(-3, -4) and (-5, -2)

OpenStudy (anonymous):

Oops, I solved it. Sorry, I was supposed to tell you what to do...

OpenStudy (anonymous):

@I_Need_Help_With_Home do u need help or no?

OpenStudy (demonchild99):

hehe...tbh i didnt even know that was you giving me answers i thought i was supposed to do another equation with it

OpenStudy (anonymous):

@The_Jokers_wife No

OpenStudy (anonymous):

Oh lol @demonchild99

OpenStudy (demonchild99):

hang on thats not one of the answer choices

OpenStudy (anonymous):

Okay Just making sure if u do just use my name

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!