Question

Help pls

Answer 1

Let f(x) = ln(x) and g(x) = log2x . For all 0 < x < 1, f(x) > g(x)

Is this false because Log(2)(x) would be bigger than ln(x) with this situation?

Answer 2

no it is true

Answer 3

Alright s: how would you test just putting .5 into both?

Answer 4

ln is red one

Answer 5

ln = log with base =e

Answer 6

ohhh that would explain >< i just put log

Answer 7

\[\log_e0.5> \log_2 0.5\]

Answer 8

Thank you for the helps :3

Answer 9

ln 0.5 =-0.6931
log_2 0.5 =-1

Answer 10

Could you check one more I just worked out just to make sure?

Let f(x) = ln(x) and g(x) = log3x . For all x >1, f(x) < g(x)

This is false because when i used 2 for both

ln(2)= .69
log(3)(x)=.63 would this not be false