Question

The equation of line EF is y = 1 over 2x + 6. Write an equation of a line parallel to line EF in slope-intercept form that contains point (0, −2)

Answer 1

is t hat \(\frac{1}{2x+6}\) or \(\frac{1}{2}x+6\)

Answer 2

no :( ill put up the answer choices

Answer 3

y = −2x − 2
y = negative 1 over 2x + 2
y = 1 over 2x − 2
y = − 2x + 2

Answer 4

I'm asking you what the line EF is

Answer 5

the equation*

Answer 6

the first response you gave me

Answer 7

so \(\frac{1}{2x+6}\)

Answer 8

yes

Answer 9

wolfram says the slope would be 1, I'll test that out later
now we use the point slope form \(y-y_1=m(x-x_1)\) where \((x_1,y_1)\) is the point we want the lines to pass through

Answer 10

okay so what do I plug in?

Answer 11

m is the slope

Answer 12

and the point we want it to go through is (0, −2)

Answer 13

(0,-2)

Answer 14

mhm

Answer 15

y-(-2)=1/2(x-0) that's what i have so far plugged in

Answer 16

what I got was \(y-(-2)=1(x-0)\)
y+2=x
y=x-2

Answer 17

Thank you! omg I get how you solved it

Answer 18

now I'll do the testing thing to make sure the slope is actually 1

Answer 19

Um another quick question is 4/-3 a positive slope or a negative slope?

Answer 20

negative. positive/negative and negative/positive are negative

Answer 21

the thing I got isn't even one of the choices, hmm

Answer 22

The equation of line LM is y = 5x + 4. Write an equation of a line perpendicular to line LM in slope-intercept form that contains point (−3, 2). well how about a question that's similar to the one were trying to figure out?

Answer 23

that one's easier

Answer 24

what is the slope of LM?