Which is an equation in point-slope form of the line that passes through the points (7, 5) and (-4, -1)? A. y + 1 = 6/7(x + 4) B. y + 1 = 6/11(x + 4) C. y + 4 = 11/6(x + 1) D. y - 1 = 6/11(x - 4)
\[y-y _{1}/x-x _{1}\]
so say subtracting the second from the first we have 5-(-1) / 7-(-4) the y values over the x values
i still dont understand
slope is rise over run or y over x right?
yea
so a slope of 1/3 would be up 1 on the y axis and right 3 which is the x axis
ok
so to find the slope of two points you use the equation y-y1/ x-x1 to get a y / x value
ok
so you choose one of the point pairs and subtract those from the other pairs
thx
so if we decide to subtract the second pair from the first pair then the first set of (x,y) values are (7,5) and the second set are (-4,-1) so you would subtract the second y value from the first and the second x value from the first
you go either way it doesnt matter if you choose to subtract the first values from the second as long as you remain consistant
but subtracting the second y value from the first you have 5-(-1) for the rise and for the run you subtract the second x value from the first so 7-(-4) for the run
this gives you a slope of 5-(-1) / 7-(-4) = 6/11 right?
are you following so far?
yes
ok so with a slope of 6/11 to find the equation you insert one of the set of points and the slope you just found into the formula y-y1 = m(x+x1)
m is the slope and y1 and x1 are the values you will replace so choosing a set of points say the second set and inserting those into the formula we have y-(-1)=6/11(x-(-4))
you cannot use the y value from set 2 and the x value from set 1
can you close the problem please
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