Question

help me!!!!!! http://assets.openstudy.com/updates/attachments/4f9f87b7e4b01d279f25d0f0-kaytree16-1335855060605-introductiontriangles_writingassignment.pdf

Answer 1

2/3 RW = RU ?

Answer 2

you still haven't told me the full answer :(

Answer 3

im really bad at geometry yall sorry

Answer 4

help

Answer 5

which is smaller in the figure .... RW or RU

Answer 6

u want the website so you could see it yourself?

Answer 7

here it is anyways


http://assets.openstudy.com/updates/attachments/4f9f87b7e4b01d279f25d0f0-kaytree16-1335855060605-introductiontriangles_writingassignment.pdf

Answer 8

rw is the smallest tho

Answer 9

if RW is smaller ..... then RU can't be two-thirds of RW ..... because that would make RU smaller

Answer 10

ok....and

Answer 11

#2 help please?

Answer 12

in fact since W is the centroid (point where all the medians meet): \[RW= \frac23RU\]

Answer 13

the same relation ship between QW and QT

Answer 14

the centroid divides a median in the ratio : 2:1

Answer 15

\[QW = \frac23 QT\]

\[\implies QT = \frac32QW\]

Answer 16

ok :)

Answer 17

\[QT= \frac32 \times27\\={81\over2}\\=40.5\]

Answer 18

perfect i think on #2 Jordan is right.....wat do u think?

Answer 19

Well i can see RT cuts QS in half... so RT bisects QS.

But how do we know that RT is also PERPENDICULAR to QS ???

Answer 20

well you can see that there r them tick marks on both side from the line dividing the triangle....right

Answer 21

they most equal the same...right?

Answer 22

right QT = TS

but we also need to show they are perpendicular .... (only then we have a \(perpendicular\) bisector)

Answer 23

mmmm true....

Answer 24

look im sorry i skyped 9th grade and im like totaly lost on 10th grade -.-

Answer 25

do we have enough info to show: \(RT \perp QS\)

Answer 26

not really

Answer 27

so robert is right

Answer 28

one easy way we could have known that is if they had marked it

but they din't

Answer 29

yea

Answer 30

We could also have know that R is on the Perpendicular Bisector if they had marked RQ=RS. (because any point on Perpendicular Bisector must be equidistant to the endpoints) ...but we don't have that either

Answer 31

right therefore robert was right....alright now was up with #3? i think its wrong 100%

Answer 32

basically any info that could prove \(\triangle RQT \cong \triangle RST\) would have made RT the perpendicular bisector

Answer 33

thankx so #3

Answer 34

so, you need 2 ways to prove that angles are wrong...

Answer 35

can you think of one

Answer 36

if you add all the sides , they equal to 268 degrees instead of 180 degress

Answer 37

what does the sum of all the angles of a triangle have to be ?

Answer 38

not sides, angles. but you are correct that's one reason.

Answer 39

before we do the second reason we should look at #4.

Answer 40

ok

Answer 41

what did you say for number 4

Answer 42

your the boss....for #4...

Answer 43

they all equal 180 there fore it most be an obtuse triangle

Answer 44

who's correct Joey, or Robin?

Answer 45

joey

Answer 46

(you are right), but what about Robin's point: there is only one obtuse angle in the triangle.... BUT there are still 2 acute angles

Answer 47

ok thats true but ....

Answer 48

what would happen if we tried to make a triangle with 2 obtuse angles

Answer 49

the first obtuse angle is more 90 degrees, the 2nd obtuse angle is more than 90 degrees....

Answer 50

so the sum of the two obtuse angles would have to be MORE than 180. correct?

Answer 51

but that is not allowed

Answer 52

ok ok so ...

Answer 53

you can try drawing 2 obtuse angles


and you'll see the sides can never meet to form a triangle