Question

help please????



Graph a triangle (XYZ) and reflect it over the line y=-x to create triangle X'Y'Z'.
Part 1: Describe the transformation using words.
Part 2: Draw a line segment from point X to the reflecting line, and then draw a line segment from point X' to the reflecting line. What do you notice about the two line segments you drew?
Part 3: Do you think you would see the same characteristic if you drew the line segment connecting Y with the reflecting line and then Y' with the reflecting line? How do you know?

Answer 1

@ganeshie8

Answer 2

do u have geogebra ?

Answer 3

nope why?

Answer 4

Okay, pick 3 points as vertices of triangle XYZ

Answer 5

how do I figure out the 3 points

Answer 6

you may pick any 3 points that form a triangle

Answer 7

a.) (1,1)
b.) (2,5)
c.) (3,2)

Answer 8

Excellent! Call them X, Y, Z instead of a,b,c

Answer 9

b/c thats what the question asks u to name them

Answer 10

X = (1,1)
Y = (2, 5)
Z = (3, 2)

fine ?

Answer 11

yes

Answer 12

here it is
http://prntscr.com/5576ga

Answer 13

next, reflect it over y = -x line

Answer 14

remember the rule for reflecting over y=-x ?

Answer 15

(x, y) --> (y, x)

Answer 16

rule: switch the x and y coordinates

Answer 17

very close, but no

Answer 18

(x, y) --> (y, x) is the rule for reflecting over line `y = x`

Answer 19

use below for reflecting over the line `y = -x` :

(x, y) --> (-y, -x)

Answer 20

reflect the vertices of triangle, what do u get ?

Answer 21

X' = ?
Y' = ?
Z' = ?

Answer 22

X = (1,1) --> (-1,-1)
Y = (2, 5)--> (-5,-2)
Z = (3, 2)--> (-2,-3)

Answer 23

Looks good! see how the triangle looks after reflection over y=-x line :

http://prntscr.com/5576wj

Answer 24

so are we done with part1 ?

Answer 25

so part 1 answer will look like this?:
part 1.) use the rule for reflecting over the line y = -x :
(x, y) --> (-y, -x)
X = (1,1) becomes (-1,-1)
Y = (2, 5) becomes (-5,-2)
Z = (3, 2) becomes (-2,-3)

Answer 26

yes also describe the rule in words

Answer 27

like :

to reflect the line over y=-x line, we switch the x and y coordinates, next negate the coordinates... etc..

Answer 28

okay now part 2

Answer 29

for part2 :

http://prntscr.com/5577wr

Notice that the segment X and X' is `perpendicular` to the line of reflection.

Answer 30

Also the segment joining X with y=-x line and
the segment joining Y' with y=-x are on the same line.

Answer 31

part 3?

Answer 32

what do you think, if u join Y and Y' to the line of reflection, will they be on same line ?

Answer 33

will they be perpendicular ?

Answer 34

yes

Answer 35

Good! put the same in few sentences and describe

Answer 36

here i have joined Y and Y'
http://prntscr.com/5579ba

Answer 37

clearly the segments joining Y and Y' to the line of reflection are on the same line

and also they seem to be perpendicular to the line of reflection

Answer 38

so the answer for part 3 would be like this?:
part 3.)the segments joining Y and Y' to the line of reflection are on the same line
and also they seem to be perpendicular to the line of reflection

Answer 39

Looks very good!

Answer 40

thanks so much :) can you help me with one more??? please, please, please?

Answer 41

wil try, post it as a new question