Question

x^3-3*x^2-9*x+27

Answer 1

What exactly do you want to do with this equation? solve for z?

Answer 2

i want to make it in groups for fraction

Answer 3

help plz

Answer 4

One sec

Answer 5

\[\ x^3-3x^2-9x+27\]\[\ \color{red}{x^3 -3x^2} + \color{blue}{-9x+27}\]

Answer 6

x^3-3*x^2-9*x+27=x^2(x-3)-9(x-3)=(x^2-9)(x-3)=(x-3)^2 (x+3) @neoo

Answer 7

You've got these 2 functions and we want to make these into 2 groups. from the red group, we can factor out the LCM, \(\ x^2\)

Answer 8

\[\ \color{red}{x^3 -3x^2} + \color{blue}{-9x+27}\]\[\ \color{red}{x^2(x-3)}+ \color{blue}{(-9x+27)}\]

Answer 9

then from the blue group, we can factor out our LCM, -9.
\[\ \color{red}{x^2(x-3)} \color{blue}{-9(x+3)}\]

Answer 10

thnks

Answer 11

notice how we have a common factor of \(\ (x-3)\)? We can group these togetehr to form \(\ (x-3)^2\)\[\ \color{green}{(x^2-9)}\color{purple}{(x-3)^2}\]

Answer 12

No problem :) Good luck!