Question

Rationalize the denominator of
Sqrt of -9/ (4-7i)-(6-6i)

Answer 1

Please helpppp

Answer 2

combine like terms in the denominator first

Answer 3

-13i

Answer 4

you should get
\[\frac{3i}{-2-i}\] if i am reading it correctly

Answer 5

No

Answer 6

That is not in my answers

Answer 7

first you have to distribute bracket by negative sign

Answer 8

i didn't say that was the answer, i said that was the first step
there is more to go

Answer 9

ok

Answer 10

because you did -7i -6i
instead -7i + 6i

Answer 11

-i

Answer 12

is this the denominator \[(4-7i)-(6-6i)
\]

Answer 13

Yes

Answer 14

remove the parentheses and combine like terms
you should get what i wrote above
try it

Answer 15

then there is a couple more steps to write this in standard form

Answer 16

Ok

Answer 17

I got that what do i do now

Answer 18

\[\frac{3i}{-2-i}\] multiply top and bottom by the conjugate of the denominator, which is \(-2+i\)

Answer 19

\[\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}\]

Answer 20

the denominator will be \(2^2+1^2=5\)

Answer 21

the numerator will be whatever you get when you multiply

Answer 22

So -3-6i/5

Answer 23

yeah looks good

Answer 24

Ca u help with another

Answer 25

Which of the following is teh conjugate of a complex number with 2 as the real part and -4 as the imaginary part.

Answer 26

I think its 2+4i