Question

If the slower ship in the preceding exercise leaves at noon and the other at 1p.m. , how far apart are they at 2p.m....................... anyone can help me i will give medals and i will be your fan

Answer 1

@uri

Answer 2

@CaseyCarns

Answer 3

@mathmath333

Answer 4

@surjithayer

Answer 5

buddy can you help me here

Answer 6

is the question complete

Answer 7

yep

Answer 8

i think the question is lacking some information

Answer 9

wait i will check again

Answer 10

can i give another question here?

Answer 11

yes u caan

Answer 12

Point A and B are separated by an obstacle. In order to find the distance between them, a third point C is selected which is 120 yards from A and 150 yards from B. The angle ACB is measured to 80degrees 10 min. Find the distance from A to B.
CAN YOU USE THE COSINE LAW...AND CAN U DRAW THE FIGURE BUDDY :D

Answer 13

mr. math math can you show me the solution?

Answer 14

law of cosines is used here
http://www.mathsisfun.com/algebra/trig-cosine-law.html

Answer 15

tnx

Answer 16

\(\large\tt \begin{align} \color{black}{cosC=\dfrac{AC^2+BC^2-AB^2}{2\times AB\times BC }\\~\\
cos(80+\frac{1}{6})=\dfrac{120^2+150^2-AB^2}{2\times 150\times 120}\\~\\
cos(80+\frac{1}{6})\times 2\times 150\times 120=120^2+150^2-AB^2\\~\\
AB^2=120^2+150^2- cos(80+\frac{1}{6})\times 2\times 150\times 120\\~\\
AB \approx \pm 175}\end{align}\)