Question

Can someone please check this, i don't think i'm working it out right....
2n-1 >/= 8n-1
I got n /= greater than or equal to

Answer 1

@hilbertboy96

Answer 2

So we have

\[2n-1\ge8n-1\]

We wish to solve for n. We need to get n on one side so first thing we can do is add one to the right which cancels the 1's and we get

\[2n \ge8n\]

subtract 8n to the other side we get

\[-6n \ge0\]

Now we divide by negative six and WHEN YOU DIVIDE BY A NEGATIVE THE SIGN FLIPS (Caps for emphasis) so we get

\[n \le0\]

Yes you were correct

Answer 3

fwew ! thanks do you have time to check just a couple more? im confused on a few

Answer 4

Yep

Answer 5

it's 7-7p >/= 7- 10p

I somehow got p </= 0 buti dont think its right (not for sure)

Answer 6

@hilbertboy96

Answer 7

Ok following same method

\[7-7p \ge7-10p\]

Subtract 7 from both sides they cancel add 10p to the left and we have

\[3p \ge0\]

Divide by 3 now this time sign does not change since we are dividing by a positive

\[p \ge0\]

Answer 8

how is -7 and -10 =3?

Answer 9

you are adding 10p to both sides to cancel it on the right and -7+10=3

Answer 10

oh okay :) what about 2n-1 >/= 8n-1
I got n</= 0 .... not sure if its right

Answer 11

Thats the one you already asked :P You were correct

Answer 12

oh duhhh lol my bad haha ok what about 3-4x < 8x+3
I can't figure this one out :P

Answer 13

Ok well we subtract 3 from both sides and get

-4x<8x

Next we subtract 8x from both sides to isolate x on one side

-12x<0

Divide by -12 to get x by itself and flip signs since dividing by a negative

x>0

Answer 14

okay well that is what i got too, so thats good what about 5x-5 > 6x+10 I got x < -15

Answer 15

Add 5 to both sides

5x>6x+15

Subtract 6x from both sides

-x>15

Divide by -1 (flip sign)

x<15

Answer 16

isn't 15/ -1 = -15 ?

Answer 17

oh yea xD sorry

Answer 18

okay what about 9-5x < -4x +3
I got x>6

Answer 19

subtract 9 from both sides we get

-5x < -4x -6

Add 4x to both sides

-x < -6

Divide by negative six and flip sign

x > 6

Answer 20

okay well it seems i did all those right (yayy!!!) okay give me a second to type in this next one

Answer 21

Ok!

Answer 22

\[\left| 3-9x \right| \ge 39\]

I got x </= -4 and x >/= -4 2/3 .... not sure though

Answer 23

Ahh lord I hate these xD ok well with absolute value ones we split it up one as is one with a negative in it

So we have

\[3-9x \ge39\]

And (hopefully I am right)

\[-3x + 9 \le -39\]

Solve for both we get

\[-9x \ge 36\]
\[x \le -4\]

and

\[-3x \le -48\]
\[x \ge 16\]

Answer 24

I think I am not sure :P

Answer 25

By way this is last one :P I need to go so

Answer 26

here is how i worked it out i split it into to seperate equations ,the first one is:
3-9x >/= 39
-3 -3 (subtract 3 from both sides)
-9x >/= 36
divide both by -9
x >/= -4

and thanks for all your help, your one of my favorite people XD :D you will be missed !!!

Answer 27

Haha you will be missed also :P