Question

If cos θ=–5/13 and sin θ < 0, what is tan θ

Answer 1

\[\sin \theta = - \sqrt{1 - \cos ^{2} \theta} \]

Answer 2

solve for sin theta

Answer 3

i need to know what is tan 0

Answer 4

If sine is negative and tangent is positive, then cosine is ____?____
tangent=sine/cosine=negative/cosine=positive
=>cosine is ___?____

Is it positive or negitive?

Answer 5

negative

Answer 6

Right. You want tangent to be positive not negative. So you need cosine to be negative in order for tangent to be positive since sine is negative.

Answer 7

alright then so what is tan 0

Answer 8

sin ( 0 ) = -5/13 is given to you

Answer 9

This triangle satisfies \(\Large\rm \cos\theta=-\frac{5}{13}\).
You can use your Pythagorean Theorem to find the missing side :)

Answer 10

Sine was not given to us Sarah D: Maybe you misread it.

Answer 11

i dont understand what is tan 0

Answer 12

Tangent is `opposite` over `adjacent`, yes?
So we first need to find the length of the `opposite` side.`

Answer 13

yes

Answer 14

So use your Pythagorean Theorem:
\(\Large\rm (-5)^2+(opposite)^2=13^2\)