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OpenStudy (anonymous):
OpenStudy (anonymous):
what pics
OpenStudy (anonymous):
right there
OpenStudy (anonymous):
Duh.. Lol kidding @therealsamalbert
OpenStudy (anonymous):
huh
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OpenStudy (anonymous):
ahaha
OpenStudy (jdoe0001):
deprincessed success, we can see the pics
so.. use them :)
OpenStudy (anonymous):
which one?
OpenStudy (anonymous):
both if possible
OpenStudy (anonymous):
3 first
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OpenStudy (anonymous):
soooo what do u need help on? what is the problem that u need to figure out?
OpenStudy (anonymous):
\[A=\frac{a+b+c}{3}\] solve for \(c\) via
\[3A=a+b+c\\
3A-a-b=c\]
OpenStudy (anonymous):
i.e first step is multiply both sides by 3 to clear the fraction, second step is to subtract \(a\) and \(b\) go get \(c\) by itself
OpenStudy (anonymous):
what sides do i multiply
OpenStudy (anonymous):
for the next one \[SA=2\pi r^2+\pi rh\] first subtract and then divide
hold the phone
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OpenStudy (anonymous):
im dumb lol what do i multiply for the first one
OpenStudy (anonymous):
lets start again with this one \[A=\frac{a+b+c}{3}\]
OpenStudy (anonymous):
you want to solve for \(c\) and the first step it to get rid of that annoying 3 in the denominator
OpenStudy (anonymous):
you multiply BOTH SIDES by 3 (always both sides) to get \[3\times A=(\frac{a+b+c}{\cancel3})\times \cancel3\]\[3A=a+b+c\]
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
then to get \(c\) alone on one side, you have to get rid of the \(a\) and \(b\) by subtracting them FROM BOTH SIDES
OpenStudy (anonymous):
how do i do that
OpenStudy (anonymous):
just write it
OpenStudy (anonymous):
\[3A-a-b=c\] you don't actually subtract anything , you just write the subtraction
OpenStudy (anonymous):
oh ok
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OpenStudy (anonymous):
is that all
OpenStudy (anonymous):
yes, that is all
OpenStudy (anonymous):
now for this one \[SA=2\pi r^2+\pi rh\] you want to get \(h\) by itself
OpenStudy (anonymous):
subtract \(2\pi r^2\) from BOTH SIDES
OpenStudy (anonymous):
and now it should be clear that subtracting just means "write it"
\[SA-2\pi r^2=\pi rh\]
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
finally to get \(h\) by itself you have to get rid of the \(\pi r\) by division so divide, and again it just means "write it as a division"
\[\frac{SA-2\pi r^2}{\pi r}=h\]
OpenStudy (anonymous):
thanks so much :D
OpenStudy (anonymous):
that is all, it is confusing at first, but it really only took two steps
a)subtract
b) divide
OpenStudy (anonymous):
yw
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