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Mathematics 16 Online
OpenStudy (anonymous):

I put up a picture becuz was having difficulties

OpenStudy (anonymous):

OpenStudy (anonymous):

what pics

OpenStudy (anonymous):

right there

OpenStudy (anonymous):

Duh.. Lol kidding @therealsamalbert

OpenStudy (anonymous):

huh

OpenStudy (anonymous):

ahaha

OpenStudy (jdoe0001):

deprincessed success, we can see the pics so.. use them :)

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

both if possible

OpenStudy (anonymous):

3 first

OpenStudy (anonymous):

soooo what do u need help on? what is the problem that u need to figure out?

OpenStudy (anonymous):

\[A=\frac{a+b+c}{3}\] solve for \(c\) via \[3A=a+b+c\\ 3A-a-b=c\]

OpenStudy (anonymous):

i.e first step is multiply both sides by 3 to clear the fraction, second step is to subtract \(a\) and \(b\) go get \(c\) by itself

OpenStudy (anonymous):

what sides do i multiply

OpenStudy (anonymous):

for the next one \[SA=2\pi r^2+\pi rh\] first subtract and then divide hold the phone

OpenStudy (anonymous):

im dumb lol what do i multiply for the first one

OpenStudy (anonymous):

lets start again with this one \[A=\frac{a+b+c}{3}\]

OpenStudy (anonymous):

you want to solve for \(c\) and the first step it to get rid of that annoying 3 in the denominator

OpenStudy (anonymous):

you multiply BOTH SIDES by 3 (always both sides) to get \[3\times A=(\frac{a+b+c}{\cancel3})\times \cancel3\]\[3A=a+b+c\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then to get \(c\) alone on one side, you have to get rid of the \(a\) and \(b\) by subtracting them FROM BOTH SIDES

OpenStudy (anonymous):

how do i do that

OpenStudy (anonymous):

just write it

OpenStudy (anonymous):

\[3A-a-b=c\] you don't actually subtract anything , you just write the subtraction

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

is that all

OpenStudy (anonymous):

yes, that is all

OpenStudy (anonymous):

now for this one \[SA=2\pi r^2+\pi rh\] you want to get \(h\) by itself

OpenStudy (anonymous):

subtract \(2\pi r^2\) from BOTH SIDES

OpenStudy (anonymous):

and now it should be clear that subtracting just means "write it" \[SA-2\pi r^2=\pi rh\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

finally to get \(h\) by itself you have to get rid of the \(\pi r\) by division so divide, and again it just means "write it as a division" \[\frac{SA-2\pi r^2}{\pi r}=h\]

OpenStudy (anonymous):

thanks so much :D

OpenStudy (anonymous):

that is all, it is confusing at first, but it really only took two steps a)subtract b) divide

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

u busy or can u help me with two more

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