A large wrecking ball is held in place by two light steel cables. The mass m of the wrecking ball is 4164 kg, and θ = 36°.

(a) What is the tension in cable TB?
N

(b) What is the tension in cable TA?

Question

A large wrecking ball is held in place by two light steel cables. The mass m of the wrecking ball is 4164 kg, and θ = 36°.

(a) What is the tension in cable TB?
  N

(b) What is the tension in cable TA?

anonymous · Answer

attachment

surry99 · Answer

Draw a FBD of the ball and apply Newtons second law

anonymous · Answer

but how???

surry99 · Answer

what is the definition of a free body diagram?

surry99 · Answer

It is a diagram showing all the external forces acting on a body of interest.
Here, you want a fbd of the wrecking ball...how many external forces act on it?

anonymous · Answer

gravity and the two ropes, so three?

surry99 · Answer

yes, so try to draw the fbd of the wrecking ball with the forces pointing in the correct directions

anonymous · Answer

|dw:1415853615410:dw|

surry99 · Answer

hang ...on|dw:1415853752381:dw|

surry99 · Answer

ok, so I now added the coordinate system because you can now apply Newtons second law in both directions.
You will need however to break the Tb vector into components|dw:1415853919567:dw| in the x and y directions using the angle 36 degrees.

anonymous · Answer

but how D: I don't have enough info

anonymous · Answer

would you use tangent?

surry99 · Answer

Yes you do,,,,the vertical component of Tb is Tb (cos36)
and the horizontal component is Tb (sin36)
Now if you apply Newtons second law in the x direction :
Ta = Tb(sin36)
In the y direction:
Tb(cos36) = mg = 40807 N
So , you can solve for Tb then get Ta.

anonymous · Answer

i dont understand how do i put that into the calculator

anonymous · Answer

what is the answer how do u get that

surry99 · Answer

|dw:1415854540570:dw|