Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

MEDAL!!!

OpenStudy (anonymous):

Water coming out from a fountain is modeled by the function f(x) = -x2 + 6x + 6 where f(x) represents the height, in feet, of the water from the fountain at different times x, in seconds. What does the average rate of change of f(x) from x = 2 to x = 5 represent? The water travels an average distance of 4 feet from 2 seconds to 5 seconds. The water travels an average distance of 1 foot from 2 seconds to 5 seconds. The water falls down with an average speed of 2 feet per second from 2 seconds to 5 seconds. The water falls down with an average speed of 1 foot per second from 2 seconds to 5 seconds.

OpenStudy (anonymous):

@iGreen what about this one? i am not sure what it is at all...

OpenStudy (anonymous):

@RolyPoly @mathmath333

OpenStudy (anonymous):

@Destinymasha @AnswerMyQuestions

OpenStudy (anonymous):

@iGreen ..?

OpenStudy (igreen):

Hold on, getting tagged so much.

OpenStudy (igreen):

It's asking what the AVERAGE RATE OF CHANGE is between x = 2 and x = 5. Where x = seconds. What do you think the answer is? @SouthernRebel101

OpenStudy (mathmath333):

\(\large\tt \begin{align} \color{black}{f(x) = -x^2 + 6x + 6\\~\\ f(5) = -(5)^2 + 6(5) + 6\\~\\ =11\\~\\ f(2) = -(2)^2 + 6(2) + 6\\~\\ =14\\~\\ \text{average rate of change of f(x) from x = 2 to x = 5}\\~\\ =\dfrac{f(5)-f(2)}{5-2}\\~\\ =\dfrac{11-14}{5-2}\\~\\ =-1}\end{align}\) so, The water falls down with an average speed of 1 foot per second from 2 seconds to 5 seconds

OpenStudy (anonymous):

C od D i think, not sure really

OpenStudy (anonymous):

TY SO MUCH! can you help with some more?

OpenStudy (mathmath333):

sry hve to go , i will try after sometime

OpenStudy (anonymous):

aww okay

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!