An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 6275 J. What is the specific heat of the gas?

Question

cuanchi · Answer

delta E = q+w

q= delta E- w = m x C x deltaT

C=delta E- w /(m  x deltaT)

delta E= 6275 (it is positive the system increase the energy)
w= -346J  (it is negative the system release work)
m=80.0g
delta T= Tf-Ti= 225-25= 200  (it is positive the system increase its temperature

anonymous · Answer

Thank you