Quadratic Equation | Is my answer correct? http://gyazo.com/e11e566bf7bebd14455dff7c75e86e2b
Please, not all at once. D:
there are many ways to approach this so there is no 'correct first step'. if you are expected to go by some method prescribed in your material, then you will have to share that material.
It wants me to show the first step on making it into this format:
i can do any of the options and still reach a final conclusion ....
(x-p)^2 = q
So basically, the first step to converting it.
May I show you what I think?
please do
Hm.
GIve me a second please
Sorry.
focus on making a complete square
Yes, so (x - 9) * (x-9)
Then (x-9)^2
(x+9)^2 yes what do we get when we expand it?
x-9 squares out to -18x which is not correct
I'm not too sure what to do then, in that case.
Tell me what you think
do you agree that we want (x+9)^2 ??
Does it correspond to the answer to my problem?
(x+n)^2 = x^2 + 2n x + n^2 therefore 2n = 18 when n=9 (x+9)^2 = x^2 + 18x + 81
as such, we want to convert the last term: 76+x = 81 when x=?
x = 5
then lets add x to each side, and x=5
So then we subtract 5!
oh XD
So then my answer would be B, amistre?
x^2 + 18x + 76 + x = 0 + x x^2 + 18x + 76 + 5 = 5 x^2 + 18x + 81 = 5
yes add 5 :) B is fine
Thanks, you helped a lot :DDD
now, if we add 9 and then subtract 4, we have still gotten to adding a net of 5, so A works as a first step if we subtract 5 and add 10, then we have added a net of 5 and C works as a first step if we subtract 9 and add 14, then we have added a net of 5 and D works as a first step
but if we add 5 and subtract nothing, we have added a net of 5 an B is the 'quickest' option
Yes.
as you can see, i can 'start' with any of the options as a first step and still get to the final conclusion. so the questionis simply worded poorly
Yeah, FLVS is known for that ;)
Thanks again.
good luck :)
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