Question

I am stuck on this question in my physics pre-lecture assignment. There is more than one correct answer. The question is attached to the post below.

Thank You.

Answer 1

You have learned that the period of a wave is 1/ the frequency of the wave length, or \[T=\frac{1}{f}\] If we were to rearrange this equation to solve for frequency, what would we get?

Answer 2

frequency=1/T

Answer 3

Already tried it alone there is more than one answer

Answer 4

@PaxPolaris

Answer 5

Any ideas?

Answer 6

2 4 and 5 ... i think

Answer 7

That was correct thank you!

Answer 8

@Jhannybean

if we have 1 oscillation in \(T\) seconds:

wave Period = \(T\) seconds per oscillation

wave frequency = \(1/T\) oscillations per second
^^^^ from the units for frequency you can see why 5 has to be true.


And finally, \(1\) oscillation = \(1\) complete cycle = \(2\pi\) radians

so angular frequency, which is in radians per second, equals \(2\pi\) times the wave frequency in oscillations per seconds

Answer 9

Oh that makes things a lot more clear now. Thank you very much for this.

Answer 10

note: 1 oscillation, and 1 radian are both actually unitless.

so science textbooks measure Period in \(s\), and both angular and wave frequencies in \(s^{-1}\) or\(hertz\)

...i just find it useful to include oscillations and radians as if they were real units .. .to make it less confusing.

Answer 11

Yeah I agree.